Does a position operator acting on a wavefunction give a position eignenfunction?
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Yes, if the wavefunctions are eigenfunctions of the position operator ;) |
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There is a position operator. The operator is just the position variable. The eigenfunction equation is XΨ = x0Ψ where X is the position operator and x0 is the eigenvalue. In configuration space, this becomes xΨ = x0Ψ where x is the position variable. The eigenfunction is the Dirac delta function Ψ(x) = δ(x - x0). This is a weird function. It has two key properties. First, it is zero everywhere except at the single point x=x0, where it is infinite. Second, its integral from minus infinity to plus infinity is equal to one, ∫-∞∞ δ(x - x0) dx = 1. |
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